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How about ... F(x)^[3] + 2 F(x)^[2] = exp(x) ?

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How about ... F(x)^[3] + 2 F(x)^[2] = exp(x) ?
tommy1729 Offline
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#3
03/07/2016, 09:07 PM
Maybe start the iteration with exp^[1/3](x).

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Tommy1729
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RE: How about ... F(x)^[3] + 2 F(x)^[2] = exp(x) ? - by tommy1729 - 03/07/2016, 09:07 PM



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