05/12/2021, 12:16 PM
(05/11/2021, 10:05 PM)JmsNxn Wrote:(05/11/2021, 09:48 PM)MphLee Wrote: OK, I'll take time to digest this. But to be clear, I don't still understand then how can you use the omega notation on that set you define.
....
Maybe it's just an abuse of notation? When I see that Omega notation I picture it as
YES! That's absolutely it Mphlee!
Everything you are saying is correct. That's exactly how you should visualize it.
It is not an abuse of notation, for the simple reason we are MODDING OUT by the equivalence relation,
\(
\int_\gamma \simeq \int_\varphi\\
\)
The fact that this modding out works so well, is because of the following.
There is some representatives \( \gamma_1,\gamma_2 \) of \( \text{Rsd}(f,\zeta_1),\text{Rsd}(f,\zeta_2) \) respectively, such that,
\(
\int_\gamma f(s,z) = \int_{\gamma_1} \bullet \int_{\gamma_2}\\
\)
BUT, there are also some representatives \( \gamma_1^*,\gamma_2^* \) of \( \text{Rsd}(f,\zeta_2),\text{Rsd}(f,\zeta_1) \) respectively, such that,
\(
\int_\gamma f(s,z) = \int_{\gamma_1^*} \bullet \int_{\gamma_2^*}\\
\)
So when I write,
\(
\int_\gamma f(s,z)\,ds\bullet z = \Omega_{j} \text{Rsd}(f,\zeta_j;z)\bullet z\\
\)
I mean, there is SOME representative of each Rsd, where this is true. Think about modular arithmetic.
\(
x \equiv y\,\,(\text{mod} \,m)\\
\)
means there is SOME k such that,
\(
x-y = km\\
\)
It doesn't mean for all k.
So when I write \( \text{Rsd} \); I'm assuming we're in the modded out space. And when we pull back, there is SOME representative from this set where it is true. You can see this even in your fancy picture. Just reorganize the curves to put different singularities first.
Tbh Im familar with contour integration , but I did not get much out of that.
Say I take the contour for counting the amount of zero's of (Riemannzeta(s))^z - z^2.
How does that get 4 compositions ?
Im also confused by compositions of integrals.
I mean compositions are used for functions.
integrals are operators and result in values.
I do not know how to interpret composition of integrals or values , apart from maybe fractional calculus.
So Im guessing these integrals have a parameter hence being a function.
Maybe some examples might help.
Im not even sure why we are doing contour integrals in the first place ?
WHY does that matter to iteration theory ?
The Jabotinsky ilog is defined as a derivative and hence yeah we can recover by integration.
But what is the point then ??
Maybe im confused by notations.
Maybe I need to read and think more.
But It does not resonate well at the moment.
regards
tommy1729


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