Brute force tetration A_k(s) is analytic !
#7
So we're taking,

\(
G(-ks) = \int_1^\infty e^{-x}x^{-1-ks}\,dx\\
\)

which has decay to zero as \( \Re(s) \to \infty \). However, you then take,

\(
\Omega_{j=1}^\infty e^{z+G(-k(s-j))}\bullet z\\
\)

But, \( G(-k(s-j)) = G(jk-ks) \to \infty \) as \( j \to \infty \). As in,

\(
\sum_{j=1}^\infty e^{z+G(-k(s-j))} = \infty\\
\)

So I'm not sure how you are planning to derive convergence of this infinite composition.
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RE: Brute force tetration A_k(s) is analytic ! - by JmsNxn - 03/19/2021, 09:12 PM

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