12/10/2007, 03:14 AM
@Ivars
What are you talking about? The statement "h(1/x^x) * h(x^1/x) = 1" could be interpreted in at least four ways:
@Gottfried
Also, it took me 3 months to understand your graphs, but I think I understand them now. It seems like you were trying to plot a graph like this:
![[Image: selfroot-real-zeros.png]](http://tetration.itgo.com/up/selfroot-real-zeros.png)
which is the contour plot of \( \text{Im}(x^{1/x}) = 0 \). However, I still don't understand the questions your asking, which makes it hard to get through this 8-page thread. If someone could summarize the questions and results in this thread, I would be very thankful.
Andrew Robbins
What are you talking about? The statement "h(1/x^x) * h(x^1/x) = 1" could be interpreted in at least four ways:
- \( h\left(\frac{1}{x^x}\right) h\left(\frac{x^1}{x}\right) = 1 \) (with the usual order of operations), or
- \( h\left(\frac{1}{x^x}\right) h\left(x^{(1/x)}\right) = 1 \)
- \( h\left((1/x)^x\right) h\left(\frac{x^1}{x}\right) = 1 \)
- \( h\left((1/x)^x\right) h\left(x^{(1/x)}\right) = 1 \) (assuming the order of operations of "/" and "^" are opposite from their usual order)
@Gottfried
Also, it took me 3 months to understand your graphs, but I think I understand them now. It seems like you were trying to plot a graph like this:
![[Image: selfroot-real-zeros.png]](http://tetration.itgo.com/up/selfroot-real-zeros.png)
which is the contour plot of \( \text{Im}(x^{1/x}) = 0 \). However, I still don't understand the questions your asking, which makes it hard to get through this 8-page thread. If someone could summarize the questions and results in this thread, I would be very thankful.

Andrew Robbins

