11/27/2007, 07:10 PM
jaydfox Wrote:It's not 18*I, it's \( \frac{2\pi i}{\ln\left(\sqrt{2}\right)} \)
Right, sorry, thanks.
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Regular slog for base sqrt(2) - Using z=2
Regular slog for base sqrt(2) - Using z=2
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Regular slog for base sqrt(2) - Using z=2
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