pentation and hexation
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pentation and hexation
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08/21/2017, 08:05 PM
Hey Sheldon. Bo proved this somewhere on here. It's actually pretty straight forward to prove that ANY analytic hyper-operator necessarily satisfies \( f(-k) = 1-k \) for \( 0 \le k \le n-1 \) for \( n \) the rank of the hyper-operator. (exponentiation is rank 1, tetration is rank 2, pentation is rank 3, hexation is rank 4, so on and so forth.)
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pentation and hexation - by sheldonison - 08/07/2017, 07:33 PM
RE: pentation and hexation - by JmsNxn - 08/21/2017, 08:05 PM
RE: pentation and hexation - by sheldonison - 08/22/2017, 02:03 PM
RE: pentation and hexation - by JmsNxn - 08/22/2017, 10:38 PM
RE: pentation and hexation - by sheldonison - 09/03/2017, 10:11 PM
RE: pentation and hexation - by JmsNxn - 09/03/2017, 11:52 PM
RE: pentation and hexation - by sheldonison - 09/04/2017, 03:04 AM
RE: pentation and hexation - by JmsNxn - 09/04/2017, 04:07 AM
RE: pentation and hexation - by Ember Edison - 09/18/2019, 06:34 AM
RE: pentation and hexation - by sheldonison - 09/18/2019, 02:34 PM
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