10/26/2015, 01:07 AM
I doubt 3sinh method would be identical to 2sinh method.
Need to reconsider Some things.
Regards
Tommy1729
Need to reconsider Some things.
Regards
Tommy1729
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exp^[3/2](x) > sinh^[1/2](exp(x)) ?
exp^[3/2](x) > sinh^[1/2](exp(x)) ?
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exp^[3/2](x) > sinh^[1/2](exp(x)) ?
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| Messages In This Thread |
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exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 04/21/2015, 12:09 PM
RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 04/21/2015, 01:21 PM
RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 04/23/2015, 04:38 PM
RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by sheldonison - 04/24/2015, 12:40 AM
RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 04/23/2015, 04:54 PM
RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 04/24/2015, 02:07 PM
RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by sheldonison - 04/24/2015, 02:59 PM
RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 10/26/2015, 01:07 AM
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