Can sexp(z) be periodic ??

[tommy1729]

I wonder if sexp(z) can be periodic.

In particular 2pi i periodic....
tommy1729

L=0.318131505204764 + 1.33723570143069i, and one can develop the standard Schroder equations about the fixed points. At the fixed point, \( \lambda=L \), where \( \lambda \) is the fixed point multiplier, since \( \exp(L+\delta)=L\cdot(1+\delta)=L+\delta L \)

The definition of the formal Schroder equation, which leads to a formal Taylor series is
\( S(L)=0 \)
\( S(\exp(z)) = \lambda\cdot S( z) \)

So then
\( \exp^{oz} = S^{-1}(\lambda^z)\;\;\;\text{period}=\frac{2\pi }{\ln(L)}=\frac{2\pi }{L}\;\approx \;4.4469+1.05794i \)

The \( S^{-1}(\lambda^z) \) super function is also entire. Of course, the Schroder function of 0,1,e,e^e, are all singularities... so this function needs a lot of work to become the real valued sexp(z) we use for Tetration, but it is the starting point...

But the Schroder function does not give a real-analytic sexp.

I prefer not to " abuse " notation.

\( S(L)=0 \)
\( S(k)=1 \)
\( S(\exp(z)) = \lambda\cdot S( z) \)

So then
\( \exp^{[z]}(k) = S^{-1}(\lambda^z) \)

Im intrested in both periodic sexp's ; both real-analytic and not real-analytic.

I was thinking about other limits forms , for instance including terms like exp(z) to " force " periodicity , but I have convergeance issues that cannot be solved by analytic continuation.

regards

tomm1729