Change of base formula for Tetration
#14
andydude Wrote:
\( {}^{x + slog_b(a)}{b} = \exp_b^{[x]}(a) \)
Let me make a short unification. The slog is simply a solution to the Abel equation for \( F(x)=b^x \):
\( f(F(x))=f(x)+1 \)
which is merely our initial condition written for \( f=\text{slog}_b \) instead of \( f^{-1}(x)={}^xb \).

It is well-known that this corresponds to a fractional iteration via
\( F^{\circ t}(x)=f^{-1}(f(x)+t) \)
Moreover that any fractional iteration must be of this form.
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Messages In This Thread
Change of base formula for Tetration - by jaydfox - 08/12/2007, 06:39 AM
RE: Change of base formula for Tetration - by bo198214 - 08/13/2007, 07:31 PM
RE: Parabolic Iteration - by jaydfox - 08/15/2007, 09:19 PM
RE: Parabolic Iteration - by bo198214 - 08/15/2007, 09:30 PM
RE: Parabolic Iteration - by jaydfox - 08/15/2007, 11:41 PM
RE: Parabolic Iteration - by bo198214 - 08/16/2007, 08:17 AM
RE: Parabolic Iteration - by jaydfox - 08/16/2007, 05:51 PM
RE: Parabolic Iteration - by bo198214 - 08/16/2007, 06:40 PM
RE: Parabolic Iteration - by jaydfox - 08/16/2007, 09:47 PM
RE: Parabolic Iteration - by bo198214 - 08/16/2007, 10:07 PM

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