07/14/2014, 12:27 AM
A competitor for the 2sinh method is ofcourse
ln(ln(f(exp^[2](z)))).
If we take more ln and exp iteration we also end up with a c^oo function.
But it seems to converge faster.
regards
tommy1729
ln(ln(f(exp^[2](z)))).
If we take more ln and exp iteration we also end up with a c^oo function.
But it seems to converge faster.
regards
tommy1729

