Oh! Now I get it, you showed how to construct the continuous iterate of the base-\( e^{1/e} \) logarithm. I see now.
Good Job jaydfox, since it's a continuous iterate based on series expansion it must be related to the \( e^x - 1 \) method, and as such it is unique.
Andrew Robbins
Good Job jaydfox, since it's a continuous iterate based on series expansion it must be related to the \( e^x - 1 \) method, and as such it is unique.Andrew Robbins

