11/06/2007, 11:33 AM
jaydfox Wrote:An initial testing with the unaccelerated matrix solver shows that the \( \text{slog}_{\sqrt{2}}\left(z\right) \) has a singularity with root test of 0.5, indicating (as expected) a singularity at z=2.
Root test of \( 0.5=\lim_{n\to\infty}\sqrt[n]{a_n} \) would indicate a convergence radius of 2?
So \( \text{slog}_{\sqrt{2}} \) has a singularity at 2 and at 4?
