x^(1/x) = f^[oo](x) ??

[tommy1729]

Of course we have

f(x) = a
f(x) - a + t(x) = t(x)
t^[-1](f(x) - a + t(x)) = x

Or most(?) general

f(x) = a
A(B(f(x)) - B(a)) + C(x) = A(0) + C(x)
C^[-1] ( A(B(f(x)) - B(a)) + C(x) - A(0) ) = x

Just to be complete.

regards

tommy1729