interpolating the hyper operators
#4
I realized this is a more efficient way of talking about hyper operators. I will still talk about those \( I \) sets, but I think it is a better approach to already have an analytic expression. It came to me in a stroke of luck when I was thinking about fractional derivatives.

The goal is to have \( f(s) = \frac{1}{x[s]y} \) for all \( x,y \in \mathbb{N} \) analytic and entire. The proof of recursion then only revolves around when the output is a natural number. So we only prove for a discrete set of reals.

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Messages In This Thread
interpolating the hyper operators - by JmsNxn - 05/24/2013, 10:24 PM
RE: interpolating the hyper operators - by JmsNxn - 06/07/2013, 05:00 AM
RE: interpolating the hyper operators - by MphLee - 06/07/2013, 08:29 AM
RE: interpolating the hyper operators - by JmsNxn - 06/07/2013, 09:03 PM

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