Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ?
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Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ?
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 (02/24/2013, 06:54 AM)Balarka Sen Wrote: @cosurgi : by exp^[1/2](x) and log^[1/2](x), he means half-exponential and half-logarithms (logarithms iterated 1/2 times) not raised to the power of 1/2.oh, ok. So I don't know how to plot that  EDIT: unless you can give me some formula for half-iterated logarithm and exp. |
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Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by tommy1729 - 02/20/2013, 12:38 AM
RE: Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by tommy1729 - 02/20/2013, 10:58 PM
RE: Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by tommy1729 - 02/21/2013, 11:40 PM
RE: Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by cosurgi - 02/23/2013, 11:54 PM
RE: Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by Balarka Sen - 02/24/2013, 06:54 AM
RE: Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by cosurgi - 02/24/2013, 10:22 AM
RE: Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by Balarka Sen - 02/24/2013, 10:56 AM
RE: Behaviour of exp^[1/2](2 log^[1/2](x)) and exp^[1/2](1/2 log^[1/2](x)) ? - by tommy1729 - 02/26/2013, 11:33 PM
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