06/08/2011, 09:14 PM
(06/08/2011, 08:32 PM)sheldonison Wrote: So, now, I'm going to define the function f(b), which returns the base which has the fixed point of "b".
\( f(e)=\eta \), since e is the fixed point of b=\( \eta \)
\( f(2)=\sqrt{2} \), since 2 is the lower fixed point of b=sqrt(2)
\( f(3)=1.442249570 \), since 3 is the upper fixed point of this base
\( f(4)=\sqrt{2} \), since 4 is the upper fixed point of b=sqrt(2)
\( f(5)=1.379729661 \), since 5 is the upper fixed point of this base
I don't know how to calculate the base from the fixed point, but that's the function we need, and we would like the function to be analytic!
Oh, Sheldon seems to be quite tired from all the calculation and discussion.
Sheldon, give your self some time to rest!
Your function is \( f(z)=z^{1/z} \)
