06/02/2011, 09:12 PM
(06/02/2011, 04:58 PM)sheldonison Wrote: For base exp(1/e), there have been many posts that the half-iterate of \( \text{sexp}_\eta(z) \) is not analytic at z=e.
wow euh ...
for starters i think you meant something else from what you actually said.
i do not believe you consider half-iterates of any superfunction.
if i get it correctly :
the uppersuperfunction of eta^z is called cheta(z)
the lowersuperfunction of eta^z is called sexp(z)
you claim both cheta(z) and sexp(z) are not analytic at z = e.
that is because e is the fixpoint of eta^z and it has f ' (e) = 1.
since f(z) is not analytic at e , its taylor series is only an approximation.
just like with e^z - 1.

