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An alternate power series representation for ln(x)

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An alternate power series representation for ln(x)
JmsNxn Offline
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#8
05/09/2011, 01:02 AM
(05/08/2011, 08:28 PM)bo198214 Wrote: Oh thats just:
\( \frac{1}{e^{an}}(x-e^a)^n=\frac{(x-e^a)^n}{(e^a)^n} = \left(\frac{x-e^a}{e^a}\right)^n = \left(\frac{x}{e^a} - 1\right)^n \)


Oh that's so simple! Thanks for the help.
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RE: An alternate power series representation for ln(x) - by JmsNxn - 05/09/2011, 01:02 AM

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