z^^z ?
#12
About the complex tetration thing...

I thought (intuitively) that:

e^^xi=cos(x)+sin(x)i

e^^2xi=cos(cos(x)+sin(x)i) + sin(cos(x)+sin(x)i))

e^^3xi=cos(cos(cos(x)+sin(x)i) + sin(cos(x)+sin(x)i)))
sin(cos(cos(x)+sin(x)i) + sin(cos(x)+sin(x)i)))

e^^kxi=cos(cos(cos(cos(x)+sin(x)i) + sin(cos(x)+sin(x)i)))
sin(cos(cos(x)+sin(x)i) + sin(cos(x)+sin(x)i)))) +....2^k times
sin(cos(cos(cos(x)+sin(x)i) + sin(cos(x)+sin(x)i)))
sin(cos(cos(x)+sin(x)i) + sin(cos(x)+sin(x)i))))...etc....

But this is MERELY an intuitive hunch.

Any thoughts on the matter?
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Messages In This Thread
z^^z ? - by tommy1729 - 01/18/2011, 01:44 PM
RE: z^^z ? - by tommy1729 - 01/18/2011, 09:11 PM
RE: z^^z ? - by tommy1729 - 01/18/2011, 09:49 PM
RE: z^^z ? - by bo198214 - 01/29/2011, 10:36 AM
RE: z^^z ? - by nuninho1980 - 01/29/2011, 02:05 PM
RE: z^^z ? - by tommy1729 - 01/29/2011, 03:32 PM
RE: z^^z ? - by nuninho1980 - 01/29/2011, 11:18 PM
RE: z^^z ? - by tommy1729 - 01/30/2011, 06:41 PM
RE: z^^z ? - by nuninho1980 - 01/31/2011, 01:39 PM
RE: z^^z ? - by bo198214 - 02/27/2011, 12:55 PM
RE: z^^z ? - by tommy1729 - 02/27/2011, 11:01 PM
RE: z^^z ? - by Stan - 04/05/2011, 09:26 AM
RE: z^^z ? - by tommy1729 - 04/06/2011, 03:15 PM



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