Constructing the "analytical" formula for tetration.
#13
(02/10/2011, 04:20 AM)mike3 Wrote: ....
Letting \( r_{n, m} = \frac{u^{n-1}}{1 - u^{n-1}} \frac{m!}{n!} \left{{n \atop m}\right} \), we now have \( \chi_n = a_n \), thus an explicit, non-recursive formula for the coefficients of the regular Schroder function of the decremented exponential.
What is the decremented exponential? I'm guessing here, (I apologize for sometimes having trouble seeing the big picture behind the equations), but are these coefficients related to the superfunction of f(z)=exp(z)-1?
-Sheldon
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RE: Constructing the "analytical" formula for tetration. - by sheldonison - 02/10/2011, 05:59 AM

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