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Logarithm reciprocal

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Logarithm reciprocal
tommy1729 Offline
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#5
07/24/2010, 09:33 PM
(07/24/2010, 02:19 AM)bo198214 Wrote: News, news!

I managed to obtain a direct formula as sum:
\( a_n= \sum_{k=1}^{n} \left(n\\k\right) \frac{k(-1)^{k}}{1-c^{k}} \)

But it still doesnt remind me of something useful.
Why does this simple sequence tend to \( 1/\ln(b) \)???

i assume you mean 'b' instead of 'c' in your formula.

considering all that is written about hypergeometric series , this must be provable if true.
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Messages In This Thread
Logarithm reciprocal - by bo198214 - 07/20/2010, 04:13 AM
RE: Logarithm reciprocal - by tommy1729 - 07/20/2010, 09:11 PM
RE: Logarithm reciprocal - by bo198214 - 07/21/2010, 02:54 AM
RE: Logarithm reciprocal - by bo198214 - 07/24/2010, 02:19 AM
RE: Logarithm reciprocal - by tommy1729 - 07/24/2010, 09:33 PM
RE: Logarithm reciprocal - by bo198214 - 07/24/2010, 11:10 PM
RE: Logarithm reciprocal - by bo198214 - 08/11/2010, 02:35 AM
RE: Logarithm reciprocal - by bo198214 - 07/25/2010, 03:39 PM
RE: Logarithm reciprocal - by Gottfried - 07/26/2010, 12:14 PM
RE: Logarithm reciprocal - by bo198214 - 07/26/2010, 03:56 PM
RE: Logarithm reciprocal - by Gottfried - 07/26/2010, 05:08 PM

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