(04/22/2010, 10:20 AM)mike3 Wrote: I'm not sure if this method is going to work. Take what happens when \( n = 0 \)...
Oh thats my fault! I was too sloppy with the case \( n=0 \) the correct formula is (I changed that in my original post too):
\( \sigma(z)=\lambda+\sum_{n=1}^{\infty}\sum_{k=-\infty}^{\infty} \sigma_{n,k} e^{(\kappa n + 2\pi i k) z} \)