Regular slog for base sqrt(2) - Using z=2
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Regular slog for base sqrt(2) - Using z=2
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 (11/27/2007, 07:10 PM)andydude Wrote:jaydfox Wrote:It's not 18*I, it's \( \frac{2\pi i}{\ln\left(\sqrt{2}\right)} \) If one uses other bases in the interval 1<b<exp(exp(-1)) it seems better to express it more generally as \( \frac{2\pi i}{\ln(b)} \) where b is the base, and the upper horizontal asymptote is at \( \frac{\pi i}{2 \ln(b)} \)
Gottfried Helms, Kassel
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