Tetration extension for bases between 1 and eta
#11
(12/15/2009, 01:01 AM)dantheman163 Wrote: Upon closer study i think i have found a formula that actually works.

\( {}^ x b = \lim_{k\to \infty} \log_b ^k({}^ k b (\ln(b){}^ \infty b)^x-{}^ \infty b(\ln(b){}^ \infty b)^x+{}^ \infty b) \)

Also i have noticed that this can be more generalized to say,

if \( f(x)=b^x \)
then
\( f^n(x)= \lim_{k\to \infty} \log_b ^k( \exp_b^k(x) (\ln(b){}^ \infty b)^n-{}^ \infty b(\ln(b){}^ \infty b)^n+{}^ \infty b) \)

Actually you rediscovered the Kœnigs formula (2.24 in the (unfinished) overview paper).
\( f^{[w]}(z)=\lim_{k\to\infty}
f^{[-k]}\left((1-\lambda^{w})\cdot p+\lambda^{w}\cdot f^{[k]}(z)\right) \)
for \( f(x)=b^x \). \( \lambda \) is the derivative at the fixed point \( p={^\infty b} \), which is \( \lambda=\ln(p)=\ln(b^p)=p\ln(b)=\ln(b){^\infty b} \).

Good work!
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Messages In This Thread
RE: Tetration extension for bases between 1 and eta - by bo198214 - 12/15/2009, 01:40 AM

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