fractional powers of function inversion (was: changing terminology)

[bo198214]

and fractional "iterates of inversion" is then multivalued with complex heights according to the complex roots of -1

inv°[s](f(x)) = f°[(-1)^s](x)

Ya true, for iteration operators \( S[f]:=f^{\circ s} \) we dont need a new technique for general operator iteration, it can be reduced to powers of the exponent \( S^{\circ x}[f]=f^{\circ s^x} \).