sqrt(!) and sqrt(exp)
#2
wow. the similarity between \( !^{1 \over 2} \) and \( \exp^{1 \over 2 } \) strikes me.
just a question... why do you show the \( !^{1 \over 2} \), not the \( \mathrm{\Gamma}^{1 \over 2} \), the square root of gamma function? no, it doesn't really matter which choice, because !(z) and Gamma(z) are bassically the same: !(z-1) = gamma(z). but is it easier to extract the root of \( ! \)?
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Messages In This Thread
sqrt(!) and sqrt(exp) - by Kouznetsov - 07/29/2009, 03:41 PM
RE: sqrt(!) and sqrt(exp) - by Base-Acid Tetration - 07/29/2009, 05:03 PM
RE: sqrt(!) and sqrt(exp) - by Kouznetsov - 07/30/2009, 01:44 AM
RE: sqrt(!) and sqrt(exp) - by Kouznetsov - 08/05/2009, 08:30 AM
RE: sqrt(!) and sqrt(exp) - by Catullus - 06/08/2022, 05:32 AM

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