Gottfried Wrote:If their sign oscillate ...No, their sign doesnt oscillate.
The reason is simply: Some of the Eigenvalues are greater than 1 and hence the logarithm sequence does no more converge.
This seems to can be fixed with the series
\( \log(A)=\sum_{n=0}^\infty \frac{2}{2n+1} \left((A-I)(A+I)^{-1}\right)^{2n+1} \)
which then properly converges.
