Tetration Forum › Tetration and Related Topics › Mathematical and General Discussion v
f( f(x) ) = exp(x) solved ! ! !

Linear Mode
f( f(x) ) = exp(x) solved ! ! !
tommy1729 Offline
Ultimate Fellow
*****
Posts: 1,924
Threads: 415
Joined: Feb 2009
#21
02/11/2009, 05:32 PM
bo198214 Wrote:Existence was shown by Kneser. Uniqueness is a mostly unresearched yet. Sure is that it is not unique by analyticity alone.

well , i assume the existence of tetration ( knesers exp(F(x)) = F(x+1)) leads to existence of f(f(x)) = exp(x).

however , im not sure that f(f(x)) = exp(x) is not unique by analyticity alone ?

care to explain ?

regards

tommy1729
Website Find
Reply


Messages In This Thread
f( f(x) ) = exp(x) solved ! ! ! - by tommy1729 - 02/05/2009, 12:09 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/05/2009, 09:17 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 03:22 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 06:02 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/07/2009, 12:37 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 12:15 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 10:08 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/14/2009, 04:18 AM

Possibly Related Threads…
Thread Author Replies Views Last Post
  Has anyone solved iterations of z+Γ(z)? Leo.W 5 8,351 01/07/2022, 08:15 AM
Last Post: JmsNxn
  Means and intermediate operations (was: Rational operators (a {t} b); a,b > e solved) Cherrina_Pixie 3 14,926 06/14/2011, 09:52 PM
Last Post: JmsNxn



Users browsing this thread: 1 Guest(s)