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f( f(x) ) = exp(x) solved ! ! !

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f( f(x) ) = exp(x) solved ! ! !
tommy1729 Offline
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#15
02/10/2009, 11:17 PM
bo198214 Wrote:
tommy1729 Wrote:you do realise sqrt is not an entire function !?

thus not a counterexample.

So what, then consider \( f_n(x)=\exp(-x^{2n}) \).
Do you guess what it converges to?

ok but , does the limit f_n ( f_n (x) ) converge to a strictly rising entire function that maps R to a subset of R that has no real fixpoints ? ( disregarding removable singularities )

my f oo does : exp(x) ( again disregarding removable singularities ( x = 0 ) )

high regards

tommy1729
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Messages In This Thread
f( f(x) ) = exp(x) solved ! ! ! - by tommy1729 - 02/05/2009, 12:09 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/05/2009, 09:17 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 03:22 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 06:02 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/07/2009, 12:37 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 12:15 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 10:08 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/14/2009, 04:18 AM

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