f( f(x) ) = exp(x) solved ! ! !
#8
tommy1729 Wrote:to construct the taylor series of exp(-x^2), i take the expansion of exp(y) and substitute y = - x^2.

Well thats your choice how you compute the derivatives. But I dont see the connection to the open questions.
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Messages In This Thread
f( f(x) ) = exp(x) solved ! ! ! - by tommy1729 - 02/05/2009, 12:09 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/05/2009, 09:17 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 03:22 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 06:02 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/07/2009, 12:37 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 12:15 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 10:08 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/14/2009, 04:18 AM

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