12/14/2008, 06:37 PM
Kouznetsov Wrote:I do not understand why \( m\le n \). The sum with first 5 terms with \( n=0 \) gives the approximation of slog with function \( f \)Didnt you say that the series does not converge? Or not to the values of slog?
\( f=f(z)=\frac{1}{c}\log(z-c)+\sum_{m=0}^4 c_{m,0} (z-c)^{m} \)
shown in the figure below.
Beautiful picture btw.
