sqrt(exp)
#9
Now we have found consent Smile

Kouznetsov Wrote:
bo198214 Wrote:I mean one could expect that a half iterate has the same fixed points as the function itself.
No, One knows that if \( z^2=1 \), then it does not imply that \( z=1 \).

Well, modification: one would expect that for each fixed point of the function the half iterate has a branch with the same fixed point.

Quote:
bo198214 Wrote:And further if there is such a branch (made up at the branch point \( L \)) then I would expect that \( \sqrt{\exp}_k \) has a (maybe isolated) singularity at \( L_{e,1} \).
I doubt about "isolated". There should be a branchpoint.

So thats something left to find out Smile
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Messages In This Thread
sqrt(exp) - by Kouznetsov - 10/29/2008, 04:49 AM
RE: sqrt(exp) - by bo198214 - 10/29/2008, 08:37 PM
RE: sqrt(exp) - by bo198214 - 11/18/2008, 12:24 PM
RE: sqrt(exp) - by Kouznetsov - 11/20/2008, 02:50 AM
RE: sqrt(exp) - by bo198214 - 11/20/2008, 08:38 AM
RE: sqrt(exp) - by Kouznetsov - 11/22/2008, 01:46 AM
RE: sqrt(exp) - by bo198214 - 11/22/2008, 04:22 PM
RE: sqrt(exp) - by Kouznetsov - 11/23/2008, 12:58 AM
RE: sqrt(exp) - by bo198214 - 11/23/2008, 09:02 AM
RE: sqrt(exp) - by Kouznetsov - 11/28/2008, 12:50 AM
RE: sqrt(exp) - by bo198214 - 11/28/2008, 04:25 PM
RE: sqrt(exp) - by Kouznetsov - 11/29/2008, 02:23 PM
RE: sqrt(exp) - by bo198214 - 11/29/2008, 06:00 PM
RE: sqrt(exp) - by Kouznetsov - 12/20/2008, 01:25 PM

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