11/19/2008, 01:16 PM
Kouznetsov Wrote:bo198214 Wrote:Proof. Let \( g,h \) be two function that satisfy the above conditions. Then the function \( \delta(z)=g^{-1}(h(z)) \) is holomorphic on \( S \) (because \( h(S)\subseteq G \) and (3)) and satisfies \( h(z)=g(\delta(z)) \)...Why \( h \)? There was no \( h \) above. Should not be \( f \)?
\( h \) and \( g \) are two functions that satisfy the above conditions, as I wrote. Perhaps write better: "Let \( f=g \) and \( f=h \) be two solutions of the above conditions."