ramanujan and tetration
#5
Yep, found it.

The function \( f(x) \) defined as series of n times iterated exponential \( \exp^{\circ n}_e(x) \) (with base e) terms divided by corresponding n-th hyperfactorials (2^3^4^...n....) is on p. 326-327, Berndt, Ramanujan Notebooks, Vol 1., in excerpts from Second Quaterly report. It would be interesting to see if the original contains something more.

Berndt states that it converges for every x and for every n>0 \( f(x)> \exp^{\circ n}_e(x) \).

He does not mention entire function there.

Ivars

P.S. by adhering to Berndt's endnote of giving way to formal math, we can define by simple analogy and make conjectures:

tetra e = 1+1/2^3+1/2^3^4+ .......... = 1+1/8 + rest = probably around 1,125...because of extreme slowness.

and use it as basis for taking tetra-logarithms of iterated exponential on iteration parameter ( if we have e[4] n = f(e,4,n) then basis tetra e would be used to take tetra-log f(e,4,n) = tetra-log (n). For other bases a the value would have to be adjusted. For other n-tations we need different base for penta log etc.

Further analogies may include tetra Taylor expansion, etc.
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Messages In This Thread
ramanujan and tetration - by galathaea - 05/28/2008, 08:10 AM
RE: ramanujan and tetration - by Ivars - 05/28/2008, 10:47 AM
RE: ramanujan and tetration - by galathaea - 05/28/2008, 03:19 PM
RE: ramanujan and tetration - by Gottfried - 05/28/2008, 04:12 PM
RE: ramanujan and tetration - by Ivars - 05/28/2008, 05:57 PM
RE: ramanujan and tetration - by galathaea - 05/30/2008, 04:21 AM
RE: ramanujan and tetration - by bo198214 - 05/30/2008, 06:18 AM
RE: ramanujan and tetration - by Ivars - 05/30/2008, 12:38 PM
RE: ramanujan and tetration - by Ivars - 05/29/2008, 06:39 AM
RE: ramanujan and tetration - by Ivars - 05/29/2008, 05:04 PM
RE: ramanujan and tetration - by Ivars - 05/30/2008, 07:23 AM
Thats not tetration! - by bo198214 - 05/30/2008, 07:44 AM

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