Parabolic Iteration, again
#7
I admit I didnt dive completely into your derivations.
First question what is the parabolic flow matrix?
Is it the Carleman/Bell-Matrix of parabolic iteration \( f^{\circ t}(x) \)?
Why is it then important to know the diagonals? Because the first entry is the coefficient of the series of \( f^{\circ t}(x) \)?

andydude Wrote:From these generating functions is it easy to see that parabolic iteration does not work for \( f_2 = 0 \),
which I believe has already been proven by someone, somewhere. What is interesting is that there are actually 2 reasons for this. The first reason is that there are many \( f_2 \) in the denominator, which cannot be zero, and the second reason is that if \( f_2 = 0 \), then \( z=1 \) which means t plays no part in the equations at all.

I dont get this, lets look at the double binomial formula, which should give the same coefficients if I understood that right. There are no denominators depending on the value of any \( f_k \). I only know that in hyperbolic iteration there occurs \( f_1^n-f_1 \) in the denominator.

So lets clarify the basics first Smile
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Messages In This Thread
Parabolic Iteration, again - by andydude - 04/30/2008, 10:03 AM
RE: Parabolic Iteration, again - by Ivars - 04/30/2008, 10:19 AM
RE: Parabolic Iteration, again - by andydude - 04/30/2008, 04:30 PM
RE: Parabolic Iteration, again - by Ivars - 04/30/2008, 07:02 PM
RE: Parabolic Iteration, again - by andydude - 04/30/2008, 07:34 PM
RE: Parabolic Iteration, again - by andydude - 05/03/2008, 08:10 PM
RE: Parabolic Iteration, again - by bo198214 - 05/04/2008, 07:14 AM
RE: Parabolic Iteration, again - by andydude - 05/05/2008, 05:26 AM
RE: Parabolic Iteration, again - by andydude - 05/07/2008, 12:57 AM
RE: Parabolic Iteration, again - by andydude - 05/05/2008, 08:30 AM
RE: Parabolic Iteration, again - by bo198214 - 05/05/2008, 05:33 PM
RE: Parabolic Iteration, again - by andydude - 05/14/2008, 02:56 AM

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