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Parabolic Iteration, again

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Parabolic Iteration, again
andydude Offline
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#5
04/30/2008, 07:34 PM
Ivars Wrote:Is not \( (\log(z)^2 - \log(z)) \) just \( \log(z) \)?

No, \( (\log(z)^2 - \log(z)) = \log(z)(\log(z)-1) \)
but \( (\log(z^2) - \log(z)) = \log(z) \).

Do not confuse \( \log(z)^2 \) and \( \log(z^2) \), they are two completely different functions.

Andrew Robbins
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Messages In This Thread
Parabolic Iteration, again - by andydude - 04/30/2008, 10:03 AM
RE: Parabolic Iteration, again - by Ivars - 04/30/2008, 10:19 AM
RE: Parabolic Iteration, again - by andydude - 04/30/2008, 04:30 PM
RE: Parabolic Iteration, again - by Ivars - 04/30/2008, 07:02 PM
RE: Parabolic Iteration, again - by andydude - 04/30/2008, 07:34 PM
RE: Parabolic Iteration, again - by andydude - 05/03/2008, 08:10 PM
RE: Parabolic Iteration, again - by bo198214 - 05/04/2008, 07:14 AM
RE: Parabolic Iteration, again - by andydude - 05/05/2008, 05:26 AM
RE: Parabolic Iteration, again - by andydude - 05/07/2008, 12:57 AM
RE: Parabolic Iteration, again - by andydude - 05/05/2008, 08:30 AM
RE: Parabolic Iteration, again - by bo198214 - 05/05/2008, 05:33 PM
RE: Parabolic Iteration, again - by andydude - 05/14/2008, 02:56 AM

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