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The balanced hyperop sequence

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The balanced hyperop sequence
bo198214 Offline
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#3
04/18/2008, 05:58 PM
andydude Wrote:\( x[n+1]2^t = f_n^t(x) \) as you mentioned, so
\( x[1]1 = f_0^0(x) = x \) because it is the identity function, but
\( x[1]1 = x + 1 \) by definition of addition!
therefore, \( f_0(x) = x[0]x \) cannot exist.

This is a nice proof, thanks.

Quote:... prove it differently, as I did in an email to you awhile back.

An e-mail to me? I dont remember, did I reply?
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Messages In This Thread
The balanced hyperop sequence - by bo198214 - 04/14/2008, 08:44 AM
RE: The balanced hyperop sequence - by andydude - 04/18/2008, 05:23 PM
RE: The balanced hyperop sequence - by bo198214 - 04/18/2008, 05:58 PM
RE: The balanced hyperop sequence - by bo198214 - 04/18/2008, 06:20 PM
RE: The balanced hyperop sequence - by andydude - 04/20/2008, 02:28 AM
RE: The balanced hyperop sequence - by bo198214 - 04/26/2008, 07:20 PM
RE: The balanced hyperop sequence - by bo198214 - 11/30/2009, 11:37 PM

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