Anyway, I made a graph cause it looks nice.
The part from x= 0.9-1.1 (base) is actually going to -infinity left of base=1, + infinity right of base=1 , but i did not calculate the points since then the rest of graph becomes invisible.
If the idea is right, there one can choose pairs (base<1) or triples (base>1) of real bases and heights giving 1 as a result of b[4]height.
base[4]height=1
FiniteRealTetrationsLeadingto1.bmp (Size: 47.52 KB / Downloads: 1,352)
I changed the name of the graph as it was wrong- it is finite real tetrations h of base b=a^(1/a) such that b[4]h=1 .
Ivars
The part from x= 0.9-1.1 (base) is actually going to -infinity left of base=1, + infinity right of base=1 , but i did not calculate the points since then the rest of graph becomes invisible.
If the idea is right, there one can choose pairs (base<1) or triples (base>1) of real bases and heights giving 1 as a result of b[4]height.
base[4]height=1
FiniteRealTetrationsLeadingto1.bmp (Size: 47.52 KB / Downloads: 1,352)
I changed the name of the graph as it was wrong- it is finite real tetrations h of base b=a^(1/a) such that b[4]h=1 .
Ivars
