Deriving tetration from selfroot?
#6
Since 3 was interesting number, we can consider 3rd self roots:

3^(1/3)^3= 3 which is kind of not interesting even if it involves 2 complex 3rd roots of unity in the process, and:
3^((1/3)^3)=3^(1/27) = 1,041528498.. Which is more interesting (and 26 complex values).

Second iterate of self root of 3 would be than:

3^((1/3)^(1/(3^(1/3)))= 1,289058025.. but also 4 complex values.

With 2:

2^((1/2)^2)= 2^(1/4) = +-1,189207115... and 2 complex values
(2^(1/2))^(1/((2)^(1/2)))= +-1,277703768...

With 4

4^((1/4)^4) = 4^(1/256) = +-1,005429901... and 254 complex values but:

(4^(1/4))^(1/((4)^(1/4)))= 1,277703768..=(2^(1/2))^(1/((2)^(1/2))) and .. complex values

Anyway, function "Second iterate of self root of x" where f(x)=x^(1/x)

f(f(x)) = x^(1/x)^(1/(x^(1/x))) has maximum at e and it is = 1,290005369...

And values for x=2 and x=4 are the same, but not only-there are infinitely many such paired points at this stage. e seems to remain the value giving max of any positive iterate of self root.

Ivars
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Messages In This Thread
Deriving tetration from selfroot? - by Ivars - 03/12/2008, 08:26 AM
RE: Deriving tetration from selfroot? - by Ivars - 03/20/2008, 05:36 PM
RE: Deriving tetration from selfroot? - by Ivars - 03/20/2008, 09:53 PM
RE: Deriving tetration from selfroot? - by Ivars - 03/21/2008, 07:51 AM
RE: Deriving tetration from selfroot? - by Ivars - 03/21/2008, 11:31 PM
RE: Deriving tetration from selfroot? - by Ivars - 03/22/2008, 09:52 AM
RE: Deriving tetration from selfroot? - by Ivars - 03/22/2008, 02:23 PM
RE: Deriving tetration from selfroot? - by Ivars - 03/22/2008, 03:08 PM
RE: Deriving tetration from selfroot? - by Ivars - 03/24/2008, 10:26 PM
RE: Deriving tetration from selfroot? - by Ivars - 03/25/2008, 05:52 PM
RE: Generalized recursive operators - by Ivars - 03/13/2008, 08:01 AM



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