10/09/2023, 11:24 PM
Yes your formula works and is good to know but could look a little syntax dense
a Schroeder equation is like an extended forray (like going to an exotic club or Mexican restaurant) into integrating things like Riemann sums and outderiving a variable. So because of things like iterates and dual triple and quadruple (like tetration) iterates, or gaussian strings and higher order derivatives, the Schroeder equation should be easy enough to tackle and master
it saves the trouble of isolating a variable like using a different Riemann sum by doing it with a factor
if you're having trouble remembering Schroeder just remember to make the bigger part of the Riemann sum bigger than a (nother variable
your version you could remember all the topological fields that use the symbols
a Schroeder equation is like an extended forray (like going to an exotic club or Mexican restaurant) into integrating things like Riemann sums and outderiving a variable. So because of things like iterates and dual triple and quadruple (like tetration) iterates, or gaussian strings and higher order derivatives, the Schroeder equation should be easy enough to tackle and master
it saves the trouble of isolating a variable like using a different Riemann sum by doing it with a factor
if you're having trouble remembering Schroeder just remember to make the bigger part of the Riemann sum bigger than a (nother variable
your version you could remember all the topological fields that use the symbols
