bounded derivatives and semi-group iso ( repost ?? )
#3
(02/21/2023, 06:36 AM)JmsNxn Wrote:
(02/20/2023, 12:56 AM)tommy1729 Wrote: 0 < (d/dx)^n exp^[q](x) =< (d/dx)^n exp^[q](x)

Sorry, Tommy. I can't understand your question because you've written \(a \le a\); when I know there's a typo somewhere in there. Could you elaborate?

Tongue 

Regards, James

Thanks for warning.

It is an unmature idea at the moment but I edited.

The idea is we want for n E {0,1,2,3} , q E [0,1] and x positive real :

0 < (d/dx)^n exp^[q](x) =< (d/dx)^n exp^[q + h](x)

for any positive h such that q + h =< 1.


regards

tommy1729
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RE: bounded derivatives and semi-group iso ( repost ?? ) - by tommy1729 - 02/22/2023, 12:36 AM

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