08/12/2022, 05:25 PM
(This post was last modified: 08/12/2022, 05:34 PM by Leo.W.
Edit Reason: not branket!!! a fatal typo
)
(08/12/2022, 05:18 PM)bo198214 Wrote:(08/12/2022, 05:41 AM)Leo.W Wrote: expanding \(e^t-1,f'(t),f(t)^{n+1}\) and allocate the coefficients of \([t^{-1}]\) we can arrange and get a reccurence.
Then the recurrence should prove the asymp of a_n.
What is \([t^{-1}]\)?
It's blanket notation, only for convenience to represent the coefficient of a specific term, for example let \(f(z)=z^3+2z^2-z+5-\frac{\pi}{z^2}\)
then \([z^3]f(z)=1\)
\([z^2]f(z)=2\)
\([z^1]f(z)=-1\)
\([1]f(z)=5\)
\([z^{-2}]f(z)=-\pi\)
Regards, Leo

