Continuous Hyper Bouncing Factorial
#4
(08/09/2022, 05:34 AM)Catullus Wrote:
(08/09/2022, 05:01 AM)JmsNxn Wrote: I managed to solve:

\[
\Upsilon(s+1) - \Upsilon(s) = e^{s\Upsilon(s)}\\
\]

Which turns out to be an entire function. Trying to even get close to anything near hyper factorial from here is leagues beyond me though. I have no idea. My goal was to solve "some kind of" difference equation involving exponentials.
How did you solve it, and what solution did you obtain?

Take the function:

\[
q(s,z) = z + e^{sz}\\
\]

If you take the sequence of functions:

\[
\begin{align}
&q(s-1,z)\\
&q(s-1,q(s-2,z))\\
&q(s-1,q(s-2,q(s-3,z)))\\
&\vdots\\
&\Omega_{j=1}^\infty q(s-j,z)\bullet z\\
\end{align}
\]

Then the limit was \(\Upsilon\), where \(z\) acts as an open parameter (the (spectrum) parameters exist for \(\Re(z) > 0\)).  This function satisfies the equation, by construction:

\[
q(s,\Upsilon(s,z)) = \Upsilon(s+1,z)\\
\]

Which by linear substitution satisfies:

\[
\Upsilon(s+1,z) - \Upsilon(s,z) = e^{s\Upsilon(s,z)}\\
\]

These questions get really complicated though. And Catullus, I can't answer them. I can prove general normality theorems, and convergence theorems. But everything to do with the hyper factorial is anomalous and nulls every element of my proofs.
Reply


Messages In This Thread
Continuous Hyper Bouncing Factorial - by Catullus - 08/08/2022, 10:05 AM
RE: Continuous Hyper Bouncing Factorial - by JmsNxn - 08/09/2022, 07:22 AM

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