(05/01/2009, 09:20 AM)bo198214 Wrote: For a discussion of the topic see http://math.eretrandre.org/tetrationforum/showthread.php?tid=198&pid=2411#pid2411If I click on the link to that thread it says "The specified thread does not exist.".
Conjecture
Let \( b=\sqrt{2} \). Every real function \( f \) on \( (-2,\infty) \) that satisfies:
\( f(0)=1 \)
\( f(x+1)=b^{f(x)} \)
\( f(-f(x))=-x \)
is not continuous at any point..
Why did that happen?
Please remember to stay hydrated.
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\

