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The bounded analytic semiHyper-operators

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The bounded analytic semiHyper-operators
Catullus Offline
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Question  06/29/2022, 10:37 PM
(05/27/2016, 04:03 AM)JmsNxn Wrote:
Quote:Has it fixed points?

The only fixed point of \( \uparrow \) I can think of are constant functions. Since

\( \uparrow \phi(z) = \phi^{\circ z}(1) \)
What about the successor function?
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ฅ(ﾐ⚈ ﻌ ⚈ﾐ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
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RE: The bounded analytic semiHyper-operators - by Catullus - 06/29/2022, 10:37 PM

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