06/18/2022, 12:43 AM
this is a curious thread.
But cxp(x) satisfies the nice equationÂ
f ' (x) = f( - x)
now I know you like fractional derivatives so
D^z f(x) = f( (-1)^z x)
or
D^z f(x) = f( cos(pi z) x)
???
regards
tommy1729
But cxp(x) satisfies the nice equationÂ
f ' (x) = f( - x)
now I know you like fractional derivatives so
D^z f(x) = f( (-1)^z x)
or
D^z f(x) = f( cos(pi z) x)
???
regards
tommy1729

