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"circular" operators, "circular" derivatives, and "circular" tetration.

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"circular" operators, "circular" derivatives, and "circular" tetration.
Catullus Offline
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06/17/2022, 11:36 PM (This post was last modified: 06/18/2022, 12:22 AM by Catullus.)
(06/23/2011, 12:58 AM)mike3 Wrote: Then, the inverse, the "circular logarithm", is given by

\( \mathrm{cln}(x) = \arccos\left(\frac{x}{\sqrt{2}}\right) + \frac{\pi}{4} \).
You did not rationalize your denominator. Can you imagine trying to compute x/√(2) on slide ruler, without the denominator being rationalized?
Please remember to stay hydrated.
ฅ(ﾐ⚈ ﻌ ⚈ﾐ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
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RE: "circular" operators, "circular" derivatives, and "circular" tetration. - by Catullus - 06/17/2022, 11:36 PM

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