06/14/2022, 04:31 AM
(06/14/2022, 01:16 AM)JmsNxn Wrote: You are confusing your systems of logic. Yes, in hyperreals \(e^{-\infty}\) is infinitesimal. But in the extended reals it is 0. It depends on how we interpret these equations. And as we are operating under traditional limits, and not hyperreal limits--the result stands.If e^-∞ = 0, then e^-(-∞) = 1/e^-∞ = 1/0. But you can not divide by zero.
Please remember to stay hydrated.
ฅ(ﾐ⚈ ﻌ ⚈ﾐ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
ฅ(ﾐ⚈ ﻌ ⚈ﾐ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\