Circulation and the Fast-Growing Hierarchy
#14
(06/07/2022, 11:53 AM)MphLee Wrote:
Quote:\(|\alpha|\leq\aleph_0\) does not hold for all countable ordinals. 
Yes it does, by definition of countable.

Quote:\(|\alpha|\leq\aleph_1\) does hold for all countable ordinals.
Nope it doesn't. By definition of uncountable and of \(\omega_1=\aleph_1\).
Conterproof. let \(\alpha=\omega_1\), then \(|\alpha|\leq\aleph_1\) is true but \(\alpha\) is uncountable.
Oh, you don't mean absolute value by ||.
Please remember to stay hydrated.
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
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RE: Circulation and the Fast-Growing Hierarchy - by Catullus - 06/08/2022, 03:50 AM

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