Multiple exp^[1/2](z) by same sexp ?
#11
(05/06/2014, 09:14 AM)sheldonison Wrote: All three of these half exponential functions have positive Taylor series coefficients up to around x^14 or x^15th.

This has been known to me for years.
Many of these half exponential solutions ( not just the 3 you mentioned ) have this strange property.

And why cant we easily find one that has all these coefficients positive ?

This has troubled me for a long time.

regards

tommy1729
Reply
#12
Let f(z) = sum z^n/(2^n!)
I really wonder how fast f^[a](z) grows ...

Im fascinated by my own function Rolleyes

---

A few more remarks on these slow growing functions.

Let g(z) be a real entire nonpolynomial function.

If the " growth (g(z)) = 0 " where growth is as defined by sheldon , then that g(z) is very close to its truncated Taylor series ; a polynomial.

Since g(z) is close to a polynomial this has some important implications :

It is UNLIKELY that g(z) has ONLY 1 fixpoint AND that 1 fixpoint has multiplicity 1 and derivative y with 0 < y < 1.

It follows that the fractal for g(z) is PROBABLY very similar to that of a polynomial.

Similar case for a conjugate fixpoint pair.

Many fixpoints are also a complication when considering superfunctions ...
Yet for the investigation of comparing g^[n] to sexp(n) ( or growth rate ) these superfunctions of g(z) are intresting and maybe needed ...

Another question is : I wrote UNLIKELY AND PROBABLY. Can we be more specific ?
We seem to have " growth = 0 " => implications. Does the inverse : implications => " growth = 0 " make sense ?

For instance : if we have a fractal resembling that of a polynomial , can we conclude the function has growth = 0 ??

This also brings me to the next idea :

If we want a fractal of a transcendental entire function with finite growth , do we Always end up in a fractal resembling a polynomial or one resembling exp ?
( This is somewhat suggested by the above. Note that the fractal of exp is the same as that of exp(exp) and that of exp^[1/2] ! )

If the answer to that is NO , then there are PROBABLY two types of slow functions : the ones who have polynomial-like fractals and those who dont.
( where the ones who dont, grow faster than the others )

( edited )

regards

tommy1729
Reply
#13
I edited the previous post.
Reply


Possibly Related Threads…
Thread Author Replies Views Last Post
  Two types of tetration : sexp ' > or < 1. tommy1729 3 7,961 10/17/2023, 12:06 PM
Last Post: tommy1729
Question When Does \(\displaystyle\int_{-1}^0\text{sexp}(x)\,\mathrm{d}x\) Equal \(\frac12\)? Catullus 0 2,781 10/31/2022, 11:47 PM
Last Post: Catullus
  Revitalizing an old idea : estimated fake sexp'(x) = F3(x) tommy1729 0 3,032 02/27/2022, 10:17 PM
Last Post: tommy1729
  Sexp redefined ? Exp^[a]( - 00 ). + question ( TPID 19 ??) tommy1729 0 6,059 09/06/2016, 04:23 PM
Last Post: tommy1729
  Can sexp(z) be periodic ?? tommy1729 2 13,045 01/14/2015, 01:19 PM
Last Post: tommy1729
  pseudo2periodic sexp. tommy1729 0 5,899 06/27/2014, 10:45 PM
Last Post: tommy1729
  [2014] tommy's theorem sexp ' (z) =/= 0 ? tommy1729 1 9,520 06/17/2014, 01:25 PM
Last Post: sheldonison
  entire function close to sexp ?? tommy1729 8 29,881 04/30/2014, 03:49 PM
Last Post: JmsNxn
  Is sexp(z) pseudounivalent for Re(z) > 0 ? tommy1729 3 11,870 03/26/2014, 01:24 PM
Last Post: tommy1729
  Vincent's theorem and sin(sexp) ? tommy1729 0 5,738 03/22/2014, 11:46 PM
Last Post: tommy1729



Users browsing this thread: 6 Guest(s)